The upward force exerted by the hand of each person to support the metal plate is 150.54 N.
The upward force exerted by the hands of the three people provides support on the metal plate.
The volume of air displaced by the metal isosceles plate is calculated as follows;
[tex]V = A \times d\\\\V = \frac{1}{2} ba \times d\\\\V = \frac{1}{2} \times 0.7 \times 1.35 \times 0.015\\\\V = 0.00709 \ m^3[/tex]
The mass of the metal plate is calculated as follows;
[tex]m = \rho V\\\\m = 6,500 \ kg/m^3 \ \times 0.00709 \ m^3\\\\m = 46.085 \ kg[/tex]
The upward force that must be provided by the 3 people to support the metal plate is calculated as follows;
[tex]F_n = mg\\\\F_n = 46.085 \times 9.8\\\\F_n = 451.633 \ N[/tex]
The upward force exerted by the hand of each person to support the metal plate is calculated as follows;
[tex]F_1 = F_2 = F_3 = \frac{F_n}{3} = \frac{451.633}{3} = 150.54 \ N[/tex].
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