Question

ou are running a camp of 30 students, including John and Jane. 3a.) What is the total possible ways you can arrange 2 focus groups of students one group being size 4 , and the other size 6. 3b.) What is the probability that John and Jane are not in the same group ( so either not chosen or are chosen but not in the same group).

Answer 1

If you are running a camp of 30students,

What is the total possible ways you can arrange 2 focus groups of students

$C(30,4) * C(26,6) = \frac{30!}{(4!*26!)}*\frac{26!}{(6!*20!)}\\\\ =27405*230230\\\\ =6309453150$

What is the probability that John and Jane are not in the same group

number of ways John and Jane are in the same group,

$=C(28,4) * C(24,4) = 20475*10626\\\\ =217567350$

therefore, number of ways they both are not in same group

$=6309453150-217567350\\\\ =6091885800$

probability that John and Jane are not in the same group

$=\frac{6091885800}{6309453150}\\\\ =0.9655$

For more information on probability, visit

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