Question

What is an equation of the line that passes through the point (1,-7)(1,−7) and is parallel to the line 3x+y=33x+y=3?

Answer 1

Answer:  3x+y = -4

Explanation:

Anything parallel to Ax+By = C is of the form Ax+By = D, where C and D are different values.

The given equation is 3x+y = 3. Anything parallel to this is 3x+y = D

Plug (x,y) = (1,-7) into that second equation to compute D

3x+y = D

D = 3x+y

D = 3(1)+(-7)

D = 3-7

D = -4

Therefore, our answer is 3x+y = -4

If you wanted to solve for y, then you'd get y = -3x-4. Both parallel lines have a slope of -3 but different y intercepts.