The volume of 3 M HCl solution used has been 30 mL. Thus, option C is correct.
The volume of the concentrated solution used for the preparation of the diluted solution has been given by:
[tex]M_1V_1=M_2V_2[/tex]
The initial molarity of the solution has been, [tex]M_1=3\;\rm M[/tex]
The final molarity of the sample has been, [tex]M_2= 1. 80 \;\text M[/tex]
The final volume of the solution has been, [tex]V_2=50\;\rm mL[/tex]
The volume of initial sample used has been, [tex]V_1[/tex] given by substituting the values as:
[tex]3\;\time\;V_1= 1. 80\;\times\;50\\ V_1=\dfrac{1. 80\;\times\;50}{3}\;\rm mL\\ \textit V_1=30\;mL[/tex]
The volume of 3 M HCl solution used has been 30 mL. Thus, option C is correct.
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