Question

What is the sum of the infinite geometric series? Sigma-Summation Underscript n = 1 Overscript 4 EndScripts (negative 144) (one-half) Superscript n minus 1 –288 –216 –144 –72.

Answer 1

The sum of the infinite geometric series is -288.

Given that

A finite geometric series with n = 4, a₁ = -144, and r = ½.

We have to determine

What is the sum of the infinite geometric series?

According to the question

The sum of the infinite is determined by the following formula;

$\rm S_\infty = \dfrac{a_1(1-r^n)}{1-r}$

A finite geometric series with n = 4, a₁ = -144, and r = ½.

Substitute all the values in the formula;

$\rm \rm S_\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\ S\infty = \dfrac{-144(1-\dfrac{1}{2}^{4})}{1-\dfrac{1}{2}}\\\\ \rm S_\infty = \dfrac{-144 \times \dfrac{15}{16}}{\dfrac{1}{2}}\\\\ \rm S_\infty = -270$

Therefore,

The sum of the infinite geometric series is,

$\rm S = \dfrac{a_1}{1-r}\\ \\ S = \dfrac{-144}{1-\dfrac{1}{2}}\\ \\ S = \dfrac{-144}{0.5}\\ \\ S = -288$

Hence, the sum of the infinite geometric series is -288.

To know more about Geometric Series click the link given below.

https://brainly.com/question/16037289