The length of the line segment BC is 31.2 units.
Triangle ABC is shown.
Angle ABC is a right angle.
An altitude is drawn from point B to point D on side AC to form a right angle.
The length of AD is 5 and the length of BD is 12.
What is the length of Line segment BC?
The altitude of the triangle is given by;
[tex]\rm Altitude = \sqrt{xy}[/tex]
Where x is DC and y is 5 units.
Then,
The length DC is.
[tex]\rm Altitude = \sqrt{xy}\\ \\ 12 = \sqrt{(DC) \times 5}\\ \\ \sqrt{DC } = \dfrac{12}{\sqrt{5}}\\ \\ [/tex]
Squaring on both sides
[tex]\rm DC = \dfrac{144}{5}\\ \\ DC = 28.8[/tex]
Considering right triangle BDC, use the Pythagorean theorem to find BC:
[tex]\rm BC^2 = DC^2+BD^2\\\\ BC^2 = (28.8)^2+(12)^2\\ \\ BC = \sqrt{829.44+144}\\ \\ BC = \sqrt{973.44}\\ \\ \rm BC = 31.2 \ units[/tex]
Hence, the length of the line segment BC is 31.2 units.
To know more about Pythagoras Theorem click the link given below.
https://brainly.com/question/26252222