Question

How many moles of Ba(NO3)2 are there in 0. 25 L of a 2. 00 M Ba(NO3)2 solution? Use Molarity equals StartFraction moles of solute over liters of solution EndFraction. 0. 13 mol 0. 50 mol 2. 25 mol 8. 0 mol.

Answer 1

The moles of barium nitrate in the solution has been 0.5 mol. Thus, the correct option is B.

Molarity has been defined as the moles of substance in a liter of solution. Molarity has been expressed as:

$\rm Molarity=\dfrac{Moles}{Volume}$

Computation for moles of Barium nitrate

The given barium nitrate solution has the volume of 0.25 L.

The molarity of the solution has been 2 M.

Substituting the values for the moles of Barium nitrate

$\rm 2=\dfrac{Moles}{0.25}\\ Moles=2\;\times\;0.25\;mol\\ Moles=0.5\;mol$

The moles of barium nitrate in the solution has been 0.5 mol. Thus, the correct option is B.

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