The state highway patrol radar guns use a frequency of 9.50 GHz. If you're approaching a speed trap driving 37.9 m/s, what frequency shift will your FuzzFoiler 2000 radar detector see

Respuesta :

The frequency shift your FuzzFoiler 2000 radar detector will see is 10.6 GHz.

Doppler effect

The doppler effect show the frequency shift of a source of sound relative to an observer depending on their relative motion.

The frequency shift f' = f(v ± v')/(v ± v") where

  • f = frequency of source = 9.50 GHz,
  • v = speed of sound = 330 m/s,
  • v' = speed of detector = speed of car = 37.9 m/s and
  • v" = speed of source = 0 m/s (since the highway patrol car is stationary)

Since the detector (our car) approaches the source (the radar gun), we use the positive sign in the numerator and a negative in the denominator

So, f' = f(v + v')/(v - v")

Since v" = 0, we have

f' = f(v + v')/(v - 0)

The frequency shift

f' = f(v + v')/v

Substituting the values of the variables into the equation, we have

f' = 9.50 GHz(330 m/s + 37.9 m/s)/330 m/s

f' = 9.50 GHz(367.9 m/s)/330 m/s

f' = 9.50 Ghz × 1.115

f' = 10.6 GHz

So, the frequency shift your FuzzFoiler 2000 radar detector will see is 10.6 GHz.

Learn more about Doppler effect here:

https://brainly.com/question/11419686