Question

Ed was running an experiment using magnesium (Mg). They collected a sample of liquid Mg that weighed 0.015 g and knows it has a density of 1.738 g/cm3. How many microliters of Mg does Ed have?

Answer 1

This problem is providing us with the mass and density of a sample of liquid magnesium as 0.015 g and 1.738 g/cm³, respectively. Thus the volume, in microliters, of this same is required and found to be 8.63 μL according to the following calculations:

Density:

In science, density is defined as the degree of compactness of a substance and is calculated with:

$\rho =\frac{m}{V}$

Thus, given both the mass and density, we can solve for the volume as shown below:

$V=\frac{m}{\rho }$

By plugging in, we obtain the answer in cm³ first:

$V=\frac{0.015g}{1.738g/cm^3} =0.0086cm^3$

Then, we convert it to microliters as follows:

$0.0086cm^3*\frac{1L}{1000cm^3} *\frac{1x10^6\mu L}{1L}=8.63\mu L$

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