Question

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up. What are the coordinates of B' after the translation? (1, 6) (–3, 6) (0, 0) (3, 1).

Answer 1

The coordinates of point B' are (-3, 6).

Given that

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

We have to determine

What are the coordinates of B' after the translation?

According to the question

Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).

The triangle is translated as 3 units to the left and 1 unit up.

To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.

After the given transformation the coordinates of point B' would be:

$\rm B(0, \ 5) = B (0-3, \ 5+1) = B(-3, \ 6)$

Therefore, the coordinates of point B' are (-3, 6).

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