Question

please graph! 90 points! And BRAINLIEST
Graph ​f(x)=3sin(12x)−5​. Use 3.14 for π. Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.

Answer 1

The points on the graph are:

• Midline point = (0,-5)
• Maximum point = (0.65,-2)

(a) The graph of the function

The equation of the function is given as:

$f(x) = 3\sin(12x) - 5$

See attachment for the graph of the function f(x)

(b) The midline point

This is the point that is on the line that passes through the midsegment of the function.

From the graph, a point on the midline is (0,-5)

(c) The maximum point

This is the point that is on the vertex of the function.

From the graph, a point on the midline is (5pi/24,-2)

This can be rewritten as: (0.65,-2)

Read more about trigonometry graphs at:

https://brainly.com/question/8120556

Answer 2

Answer:

(0,0) (1.75,3)

Step-by-step explanation:

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