Question

The initial temperature of a bomb calorimeter is 28. 50°C. When a chemist carries out a reaction in this calorimeter, its temperature decreases to 27. 45°C. If the calorimeter has a mass of 1. 400 kg and a specific heat of 3. 52 J/(gi°C), how much heat is absorbed by the reaction? Use q equals m C subscript p Delta T. 140 J 418 J 1,470 J 5,170 J.

Answer 1

The calorimeter is a device used to measure the heat produced during any type of reaction. It is also used to heat the capacity of the materials.

How do you calculate the heat absorbed by a reaction using a calorimeter?

$\rm Q = mc \Delta T$

Where,

• Q = heat transfer
• m = mass of a substance
• $\rm \Delta T$ = change in temperature

Now, substituting the given values, we get:

$\rm Q &= 1.4 \times 3.52 \times (27.45 - 28.5) \\ \rm Q &= - 5.17 \;or \; 5170\; Joules$

Thus, the reaction absorbs the energy of 5170 Joules.

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