Question

Copper has a Delta. Hfus = 13. 0 kJ/mol. What mass of copper releases 112. 4 kJ of heat as it freezes? Use q equals n delta H. 9. 42 g 6. 75 g 549 g 1590 g.

Answer 1

Enthalpy of Fusion is defined as the amount of heat required to change the 1 gram of solid into a liquid state without the change in temperature. It is also referred to as latent heat of fusion.

How do you calculate the Heat of Fusion?

• Q = Heat Required
• n = number of moles = mass/molar mass
• H$\rm_{fus}$ =  Heat of Fusion = 13.0 kJ/mol

Given:

$\begin{aligned} \rm Q = n \Delta H\\\\ \rm n = \dfrac{Q}{\Delta H}\\\\ \rm n = \dfrac{112.4}{13}\\\\ \rm n = 8.65 mol\\ \end{aligned}$

Now, the number of moles of copper is 8.65 mol. Calculating the mass, we get:

n = 8.65 mol

mass = 63.54 g/mol

$\rm m &= n \times M\\\\ \rm m &= 8.65 \times 63.54\\\\ \rm m = 549.42 gram$

Thus, the mass of copper required to yield heat of 112.4 kJ is 549.42 grams.

Learn more about latent heat of fusion here:

https://brainly.com/question/87248