Question

After 3.0 s, Mohammed was running at
1.2 m/s on a straight path. After 7.0 s, he
was running at 2.0 m/s. What was his
acceleration?

Answer 1

Based on the calculations, Mohammed's acceleration is equal to 0.2 $m/s^2$.

Given the following data:

• Initial time = 3.0 seconds.

• Initial velocity = 1.2 m/s.

• Final time = 7.0 seconds.

• Final velocity = 2.0 m/s.

To determine Mohammed's acceleration:

How to calculate acceleration.

In Science, the average acceleration of an object is calculated by subtracting its initial velocity from the final velocity and then dividing by change in time for the interval.

Mathematically, average acceleration is given by this formula:

$a=\frac{V\;-\;U}{t_f - t_i}$

Where:  

• V is the final velocity.

• U is the initial velocity.

• $t_i$ is the initial time measured in seconds.

• $t_f$ is the final time measured in seconds.

Substituting the given parameters into the formula, we have;

$a=\frac{2\;-\;1.2}{7.0\; - \;3.0}\\\\a=\frac{0.8}{4.0}$

Acceleration, a = 0.2 $m/s^2$

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