Question

A spherical Christmas tree ornament is 8.00 cm in diameter. What is the magnification of an object placed 12.0 cm away from the ornament

Answer 1

The magnification of the ornament is 0.25

What is magnification?:

This can be defined as the ratio of the height of an image to the height of an object, or it is the ratio of image distance to object distance.

To calculate the magnification of the ornament, first, we need to find the image distance.

Formula:

• 1/f = u⁻¹+v⁻¹.................... Equation 1

Where:

• f = Focal length of the ornament
• u = image distance
• v = object distance.

make u the subject of the equation

• u = fv/(f+v)................ Equation 2

From the question,

Given:

• f = 8/2 = 4 cm
• v = 12 cm

Substitute these values into equation 2

• u = (12×4)/(12+4)
• u = 48/16
• u = 3 cm.

Finally, to get the magnification of the ornament, we use the formula below.

• M = u/v.................. Equation 3

Where

• M = magnification of the ornament.

Substitute these values above into equation 3

• M = 3/12
• M = 0.25.

Hence, The magnification of the ornament is 0.25

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