Question

An empty beaker weighs 34.67 g.
When completely filled with water, the beaker and it’s contents have a total mass of 296.35 g. What volume does the beaker hold?

How much would the beaker and its contents weigh if it was completely filled with mercury? The density of mercury is d = 13.5g/mL.

Find the mass.

Answer 1

This problem is providing the mass of an empty beaker as 34.67 g, the mass of the beaker with water as 296.35 g and asks for the volume it can hold. Also, it asks for the mass of mercury contained in the beaker if its density is 13.5 g/mL. At the end, the results turn out to be 262.5 mL and 3,543 g.

Density:

In science, density is known as the degree of compactness of a substance, which means it can be calculated via:

$\rho =\frac{m}{V}$

Thus, given the mass of the empty beaker and the beaker with water, one can calculate the mass of water and then solve for the volume to calculate what the beaker is able to hold:

$m_w=296.35g-34.67g=261.68 g\\\\V=\frac{m}{\rho} =\frac{261.68g}{0.997 g/mL} =262.5mL$

Because the density of water is about 0.997 g/mL. Thereafter, one can calculate the mass of mercury with this volume and its given density:

$m_{Hg}=V*\rho=262.5mL*13.5\frac{g}{mL}\\ \\m_{Hg}=3543g$

Learn more about density: https://brainly.com/question/952755