How much heat is lost when 1277 g of H20 at 400 K is changed into ice at 263 K? Plz help I’ll give you brainliest 20 points
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Respuesta :

The heat lost is [tex]-7.32*10^-^5J[/tex]

The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.

Heat Transfer

This is the heat transferred from a body of higher temperature to a body of lower temperature.

[tex]Q = mc(\delta)T[/tex]

  • Q = Heat Transfer
  • m = mass = 1277g
  • ΔT  = change in temperature

[tex]\delta T = (400 - 273) - (263 - 273) = \\ \delta T = T_2 - T_1\\ \delta T = -10 - 127\\ \delta T = -137^0C[/tex]

We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.

Solving for heat transfer

[tex]Q = mc\delta T\\ Q = 1277 * 4.186 * -137\\ Q = -732336.514J[/tex]

The heat loss is approximately [tex]-7.32*10^-^5J[/tex]

Learn more on heat transfer here;

https://brainly.com/question/16055406

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