The heat lost is [tex]-7.32*10^-^5J[/tex]
The heat lost when the ice is cooled from 400k to 263K can be calculated using the formula of heat transfer.
This is the heat transferred from a body of higher temperature to a body of lower temperature.
[tex]Q = mc(\delta)T[/tex]
[tex]\delta T = (400 - 273) - (263 - 273) = \\ \delta T = T_2 - T_1\\ \delta T = -10 - 127\\ \delta T = -137^0C[/tex]
We converted the temperature from kelvin scale into Celsius scale and find the change in temperature.
Solving for heat transfer
[tex]Q = mc\delta T\\ Q = 1277 * 4.186 * -137\\ Q = -732336.514J[/tex]
The heat loss is approximately [tex]-7.32*10^-^5J[/tex]
Learn more on heat transfer here;
https://brainly.com/question/16055406