This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.
In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:
[tex]\frac{14}{16}=\frac{7.0}{8.0} [/tex]
Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:
[tex]NO_2:\frac{14}{16*2}=\frac{14}{32} =\frac{7.0}{16.0} \\ \\ N_2O_7:\frac{14*2}{16*7}=\frac{28}{112} =\frac{1.0}{4.0} [/tex]
Therefore, the results for NO₂ and N₂O₇ are 7.0:16.0 and 1.0:4.0 respectively
Learn more about atomic masses: https://brainly.com/question/5566317
