Question

Find the distance between the points listed. Use the results to find the distance from the

pitcher's rubber to the home plate in baseball.

1. (-2, -3) and (-2, 4)

2. (-7,5) and (1,-1)

6. (-2, 6) and (-10, +9)

7. (2, -12) and (70)

8. (3,-2) and (5,-3)

3. (-2, 3) and (3,-2)

4. (-6, -2) and (-7,-5)

9. (-4, 5) and (8,-4)

5. (-2, -1) and (-5, -5)

Answer 1

The second part of the question involves the use of alphabet map that

links to the results of the question.

Correct response;

• The distance is six feet six inches.

Methods used to calculate the distance

The formula for the distance between two points, (x₁, y₁), and (x₂, y₂) on

a coordinate plane is presented as follows;

$Distance =\mathbf{ \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 } }$

1. $Distance = \sqrt{(-2 - (-2))^2 + (4 - (-3))^2} = \sqrt{7^2} =\mathbf{ 7}$

2. $Distance = \sqrt{(1 - (-7))^2 + (-1 - 5)^2} = \sqrt{100} = \mathbf{10}$

3. $Distance = \sqrt{(3 - (-2))^2 + (-2 - 3)^2} = \sqrt{50} = \mathbf{5 \cdot \sqrt{2} }$

4. $Distance = \sqrt{(-7 - (-6))^2 + (-5 - (-2))^2} = \mathbf{\sqrt{10} }$

5. $Distance = \sqrt{(-5 - (-2))^2 + (-5 - (-1))^2} =\sqrt{25} = \mathbf{5}$

6. The possible correct coordinate points as obtained from an online source are;

(-2, 6) and (-10 -9)

$Distance = \sqrt{(-10 - (-2))^2 + (-9 - 6)^2} = \sqrt{8^2 + 15^2} = \sqrt{289} = \mathbf{ 17}$

7. $Distance = \sqrt{(7 - 2)^2 + (0 - (-12))^2} = \mathbf{ 13}$

8. $Distance = \sqrt{(5 -3)^2 + (-3 - (-2))^2} = \mathbf{ \sqrt{5} }$

9. $Distance = \sqrt{(8 - (-4))^2 + (-4 - 5)^2} = \sqrt{225} = \mathbf{ 15}$

The alphabet map obtained from a similar question, used for finding the

distance from the pitcher's rubber to the home plate in baseball is

presented as follows;

$\begin{array}{|c|c|c|c|c|c|c|c|c|}7&\sqrt{5} &13&15&5&\sqrt{10} &17&10&5 \cdot \sqrt{2} \\C&E&F&H&I&N&S&T&X\end{array}\right]$

The question number code to be used for finding the distance from the

pitcher's rubber obtained online and completed is presented as follows;

$\begin{array}{ccccccccccc}Corresponding \ letter& S&I&X&&F&E&E&T\\Response \ value&17&5&5\cdot \sqrt{2}&&13 &\sqrt{5} &\sqrt{5}&10 \\Question \ number &6&5&3&&7&8&8&2\\\\\\Corresponding \ letter & S&I&X&&I&N&C&H&E&S\\Response \ value & 17&5&5 \cdot \sqrt{2} &&5&\sqrt{10} &7&15&\sqrt{5}&17 \\Question \ number &6&5&3&&5&4&1&9&8&6\end{array}\right]$

Therefore;

• The distance from the pitcher's rubber to the home plate in baseball is six feet six inches.

Learn more about finding the distance between two points here:

https://brainly.com/question/12748728