Question

A 2.0 x 10^3-kilogram car travels at a constant speed of 12 meters per second around a circular curve of radius 30. meters. What is the magnitude of the centripetal acceleration of the car as it goes around the curve?

Answer 1

The magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

Circular motion

From the question, we are to determine the magnitude of the centripetal acceleration.

Centripetal acceleration can be calculated by using the formula

$a_{c} =\frac{v^{2} }{r}$

Where $a_{c}$ is the centripetal acceleration

$v$ is the velocity

and $r$ is the radius

From the given information

$v = 12 \ m/s$

and $r = 30 \ m$

Therefore,

$a_{c} =\frac{12^{2} }{30}$

$a_{c} =\frac{144 }{30}$

$a_{c} = 4.8\ m/s^{2}$

Hence, the magnitude of the centripetal acceleration of the car as it goes round the curve is 4.8 m/s²

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