Question

the quadratic expression -2k^2+7-5 will equal zero when K is
need help with this quick

Answer 1

Answer:

Answer: k must be 5/2 or 1

Step-by-step explanation:

${ \tt{ - {2k}^{2} + 7k - 5 = 0}}$

» Factorise the equation:

${ \tt{ {2k}^{2} - 7k + 5 = 0 }} \\ { \tt{(2k - 5)(k - 1) = 0}} \\ \\ { \tt{k = \frac{5}{2} \: and \: 1 }}$