Question

Expand: log20 m n5p mc001-1. Jpg mc001-2. Jpg mc001-3. Jpg mc001-4. Jpg.

Answer 1

Answer:

c

Explanation:

i have done the assignment and the other person is correct

Answer 2

In this exercise we have to use the properties of the logarithm to write it in one way, like this:

$log_{20}(m)-5log_{20}(n)-log_{20}(p)$

From these  recalling some properties of the logarithm, we find that:

• When the logarithm is equal to the base, the logarithm will always be equal to 1.

• Logarithm of any base, whose logarithm is equal to 1, will always have the result equal to 0.

• Two logarithms with the same base are equal when the logarithms are also equal.

Given the equation as:

$log_{20}(m/n^5p)\\log_{20}(m)-log_{20}(n^5p)\\log_{20}-(log_{20}(n^5)+log_{20}(p))\\log_{20}(m)-5log_{20}(n)-log_{20}(p)$

See more about logarithm at brainly.com/question/10486788