9.55 grams of CaCl2 are needed to produce 10.0 grams of NaCl.
The mass of a compound in a balanced reaction can be calculated as follows:
3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl
Based on the above equation, 3 moles of CaCl2 produces 6 moles of NaCl.
Moles of NaCl = 10g ÷ 58.5g/mol = 0.171mol
0.171 mol of NaCl will be produced by (0.171 × 3/6) = 0.086mol of CaCl2.
Mass of CaCl2 = 111g/mol × 0.086mol
Mass of CaCl2 = 9.55g
Therefore, 9.55 grams of CaCl2 are needed to produce 10.0 grams of NaCl.
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