In the control tower at a regional airport, an air traffic controller monitors two aircraft as their positions change with respect to the control tower. One plane is a cargo carrier Boeing 747 and the other plane is a Douglas DC-3. The Boeing is at an altitude of 2500 m, climbing at

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We have that for the Question " The Boeing is at an altitude of 2500 m, climbing at" it can be said that the distance is

|Rb-Rd|=23.13km

From the question we are told

In the control tower at a regional airport, an air traffic controller monitors two aircraft as their positions change with respect to the control tower. One plane is a cargo carrier Boeing 747 and the other plane is a Douglas DC-3. The Boeing is at an altitude of 2500 m, climbing at

The  Position of Boeing

Generally the equation for the position of Boeing   is mathematically given as

Rx=-2500cot(10) west

Ry=2500cot(10) north

Rz=2500 z axis

Rb=(-12.278i+7.089j+2.500k)km

Therefore

[tex]Rd=(-34.390i+3.00k)km\\\\Hence\\\\|Rb-Rd|=\sqrt{(-12.278i+7.089j+2.500k)^2+(7.089)^2+(2.3-3)^2}[/tex]

  • |Rb-Rd|=23.13km

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