Question

Factor of 64x^4y - 36x^2y

Answer 1

$64 {x}^{4} y - 36 {x}^{2} y$

Now take 4x^2y as common

$= 4 {x}^{2} y(16 {x}^{2} - 9)$

Now factorise the bracket portion using a^2 - b^2 = (a + b)(a - b) formula

$= 4 {x}^{2} y( {(4x)}^{2} - {(3)}^{2} ) \\ = 4 {x}^{2} y(4x + 3)(4x - 3)$

Answer:

${4x}^{2} y(4x + 3)(4x - 3)$

Hope you could understand.

If you have any query, feel free to ask.