Question

Maggie rides her bike down a hill. She starts from rest and accelerates
at a rate of 2.5 m/s/s. If she reaches the bottom of the hill with a final
velocity of 38 m/s, how long is the hill?

Answer 1

Answer:

288.8 m

Explanation:

v² = u² + 2as

• v= final velocity= 38m/s
• u = initial velocity = 0 m/s
• a= acceleration=  2.5 m/s²
• s = distance = ?

$s = \frac{v^{2} - u^{2} }{2 a} \\\\\\s = \frac{38^{2} }{2* 2.5}\\\\ \\s = 288.8m$

Answer 2

Answer:

288.8 m

Explanation:

v² = u² + 2as

v= final velocity= 38m/s

u = initial velocity = 0 m/s

a= acceleration= 2.5 m/s²

s = distance = ?