Answer:
There are 0.082 moles of He present.
Explanation:
You would use the equation PV=nRT for this problem.
P (must convert to atm) = 535 torr/ 0.704 atm
V = 2.85 L
n = being solved for
R= 0.082 (universal gas constant for atm)
T (must convert to Kelvin) = 24.7 celsius/ 297.85 K
This equals:
0.704(2.85)= n (0.082)(297.85)
2.0064 =24.42n
n= 0.082 moles