Question

Complete the remainder of the table for the given function rule: y= -x/3 + 2
x= -6 ,-3,0,3,6
y= 4 _ _ _ _ _​

Answer 1

Answer:

y = 3

y = 2

y = 1

y = 0

Step-by-step explanation:

Given expression;

y = (-x/3) + 2

Find:

Value of y, if x = -3

Value of y, if x = 0

Value of y, if x = 3

Value of y, if x = 6

Computation:

Value of y, if x = -3

y = (-x/3) + 2

y = (3/3) + 2

y = 3

Value of y, if x = 0

y = (-x/3) + 2

y = (-0/3) + 2

y = 2

Value of y, if x = 3

y = (-x/3) + 2

y = (-3/3) + 2

y = 1

Value of y, if x = 6

y = (-x/3) + 2

y = (-6/3) + 2

y = 0

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Answer 2

Answer:

x = -6, -3, 0, 3, 6

y = 4, 3, 2, 1, 0

Step-by-step explanation:

Input the different values of 6 into the equation: y = -x/3 + 2

When x = -3

•     y = -(-3)/3 + 2
•     y = 3/3 + 2
•     y = 1 + 2
•     y = 3

When x = 0

• y = -(0)/3 + 2
•    y = 0/3 + 2
•    y = 0 + 2
•    y = 2

When x = 3

• y = -(3)/3 + 2
•    y = -3/3 + 2
•    y = -1 + 2
•    y = 1

When x = 6

• y = -(6)/3 + 2
•    y = -6/3 + 2
•    y = -2 + 2
•    y = 0

-Chetan K