Hi there!
We can use the equation:
[tex]s = \frac{a}{1-r}[/tex]
a = initial term
r = common ratio
s = sum
Plug in the given values:
[tex]s = \frac{2}{1-\frac{1}{2}} = \frac{2}{\frac{1}{2}} = \boxed{4}[/tex]
Answer:
S∞ = 4
Step-by-step explanation:
The sum to infinity of a geometric sequence is
S∞ = [tex]\frac{a}{1-r}[/tex] ; | r | < 1
where a is the first term and r the common ratio
Here a = 2 and r = [tex]\frac{1}{2}[/tex] , then
S∞ = [tex]\frac{2}{1-\frac{1}{2} }[/tex] = [tex]\frac{2}{\frac{1}{2} }[/tex] = 4