Respuesta :

leena

Hi there!

We can use the equation:

[tex]s = \frac{a}{1-r}[/tex]

a = initial term

r = common ratio

s = sum

Plug in the given values:

[tex]s = \frac{2}{1-\frac{1}{2}} = \frac{2}{\frac{1}{2}} = \boxed{4}[/tex]

Answer:

S∞ = 4

Step-by-step explanation:

The sum to infinity of a geometric sequence is

S∞ = [tex]\frac{a}{1-r}[/tex] ; | r | < 1

where a is the first term and r the common ratio

Here a = 2 and r = [tex]\frac{1}{2}[/tex] , then

S∞ = [tex]\frac{2}{1-\frac{1}{2} }[/tex] = [tex]\frac{2}{\frac{1}{2} }[/tex] = 4

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