Question

A student solves the following equation for all possible values of x: StartFraction 8 Over x 2 EndFraction = StartFraction 2 Over x minus 4 EndFraction His solution is as follows: Step 1: 8(x â€" 4) = 2(x 2) Step 2: 4(x â€" 4) = (x 2) Step 3: 4x â€" 16 = x 2 Step 4: 3x = 18 Step 5: x = 6 He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0. Which best describes the reasonableness of the student’s solution?.

Answer 1

Answer:

Keep it simple. C is the answer

Step-by-step explanation:

Answer:

C) His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Answer 2

The student's solution is that C. the solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0.

What is an extraneous solution?

It should be noted that an extraneous solution simply means the root of a transformed equation that isn't a root of the original equation.

In this case, the solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Learn more about extraneous solution on:

https://brainly.com/question/2959656