Question

The length of a rectangle is 2 cm less than 7 times the width. The perimeter is 60 cm. Find the width and length.

Answer 1

Lets assume width=x. Then lenght its 7*x-2
We know that perimeter its 2*length+2*width=60
Now we substitute our x and 7x-2
2*(7x-2)+2x=60
14x-4+2x=60     /+4
16x=64             /:16
x=4 - its the width
7*x-2, where x=4
28-2=26 - length