Question

51. SHORT RESPONSE In the figure below, P is the
center of the circle with radius 15 inches. What
is the area of AAPB?
Р
5
90°
B
A

Answer 1

Answer:

112.5 square inches

Step-by-step explanation:

$A(\triangle\: APB) = \frac{1}{2} \: {r}^{2} \sin \theta \\ \\ = \frac{1}{2} \times {(15)}^{2} \: \sin \: 90 \degree \\ \\ = \frac{1}{2} \times 225 \times 1 \\ \\ = \frac{225}{2} \\ \\ \bold{\purple{ A(\triangle\: APB) = 112.5 \: {inches}^{2} }}$