This problem is divided into two parts.
At first we have to find the coordinates of P and Q.
Assuming that you mean “the points P and Q are both distant 5 from the origin”, the locus of points which are distant 5 from the origin is a circumference whose equation is:
2+2=(5)2
We find the coordinates of P and Q as the intersection between the circumference and the line −+1=0
on which they are located.
The solution of the linear system is (3,4)
and (−4,−3)
So P(3,4) and Q(-4,-3)
The following step consists in calculating the area of a triangle with base PQ and height equal to the distance of the line from the origin, that can be calculated with the formula:
ℎ=|0−0+1|(1)2+(−1)2√
where 0
and 0
are the coordinates of the origin. Hence, the distance is equal to 2√2
and the base PQ is equal to (3−(−4))2+(4−(−3))2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=72‾√
The area of the triangle OPQ is now equal to 12∗ℎ=72
