Answer:
Hey There!
Let's solve....
Isolate for x first which is
[tex]x = \frac{3 + 3y}{4} \\ [/tex]
[tex]substitute \: x = \frac{3 + 3y}{4} \\ \\ \brack \: 5 \times \frac{3 + 3y}{4} - 4y = 3 \\ \\ [/tex]
Now simplify...
[tex] \brack \: \frac{15 - y}{4} = 3 \\ \\ = y = \frac{15 - 3}{4} \\ \\ = \frac{12}{4} \\ simplify \\ \\ \frac{ \cancel{12} ^{3} }{ \cancel{4}^{1} } \\ x = 3[/tex]
Y=3
We need to find value of y first... now x
[tex]x = \frac{3 + 3 \times 3}{4} \\ \\ =x = \frac{3 + 9}{4} \\ \\ = x = \frac{12}{4} \\ simplify \: \frac{ \cancel{12}^{3} }{ \cancel{4} ^{1} } \\ \\ value \: of \: x = 3 [/tex]
Answer:
x = -1.3
I hope this is right, and I am sorry if this is wrong if it is! I rlly hope this helps you out and you can understand my method and the way I typed this!!
Step-by-step explanation:
We are going to use one of my fav methods! The substitution method!
Set this aside for now: 4x - 3y = 3 We gonna use this one: 5x - 4y = 3
5x - 4y = 3
= 5x - 3 = 4y
( also, the subtraction is with the 4y as a negative, so 4y would be positive if you moved it!)
Divide all of the equation by 4!
y = [tex]y = \frac{5x - 3}{4}[/tex]
Now, you take take the other equation and substitute the y with what you have above!
[tex]4x - 3 times \frac{5x - 3}{4} = 3[/tex]
you cross multiply 4( the denominator) with the other side that has only a three!
4x - 3 [tex]times 5x - 3[/tex] = 12
4x - 15x - 3 = 12
-11x - 3= 12
Move the three to the other side become positive!
-11x = 15
divide both sides by -11
x = -1.3
