Question

some help?? please :)

Answer 1

Answer:

1/2

Step-by-step explanation:

-1 + 3[(10-12)^3 ÷ (-16)]

PEMDAS

Parentheses first, working from inside out

Subtract inside the inner parenthesis

-1 + 3[(-2)^3 ÷ (-16)]

Exponent in side the parentheses

-1 + 3[-8 ÷ (-16)]

Divide

-1 + 3[1/2]

Multiply

-1 +3/2

Get a common denominator and add

-2/2 + 3/2

1/2

Answer 2

Answer:

The answer is 0.5.

Step-by-step explanation:

Solution :

To solve the above equation we will follow the BODMAS rule.

• >> BODMAS is an order of mathematic operations.
• >> BODMAS rule is to be followed while solving expressions in mathematics.

It stands for :

$\quad\begin{gathered} \small \begin{array}{l} \star \: \rm B= bracket \\\star \: \rm O= order \: of \: power \: \\\star \: \rm D= division \\\star \: \rm M= multiplication \\ \star \: \rm A= addition \\ \star \: \rm S=subtraction \end{array}\end{gathered}$

Evaluate the expression using the order of operations.

$= \tt{ - 1 + 3\Big[(10 - 12)^{3} \div ( - 16) \Big]}$

$= \tt{ - 1 + 3\Big[( - 2)^{3} \div ( - 16) \Big]}$

${ = \tt{ - 1 + 3\Big[( - 2 \times - 2 \times - 2) \div ( - 16) \Big]}}$

${ = \tt{ - 1 + 3\Big[( - 2 \times 4) \div ( - 16) \Big]}}$

${ = \tt{ - 1 + 3\Big[( - 8) \div ( - 16) \Big]}}$

${ = \tt{ - 1 + 3\bigg[ \dfrac{ - 8}{ - 16} \bigg]}}$

${ = \tt{ - 1 + 3\bigg[ \dfrac{ \cancel{ -} 8}{ \cancel{ -}16} \bigg]}}$

${ = \tt{ - 1 + 3\bigg[ \: \dfrac{8}{16} \: \bigg]}}$

${ = \tt{ - 1 + 3\bigg[ \: \cancel{ \dfrac{8}{16}} \: \bigg]}}$

${ = \tt{ - 1 + 3\bigg[ \: \: \dfrac{1}{2} \: \: \bigg]}}$

${ = \tt{ - 1 + 3\bigg[ \: \: \cancel{\dfrac{1}{2}}\: \: \bigg]}}$

${ = \tt{ - 1 + 3\big[ 0.5\big]}}$

${ = \tt{ - 1 + 3 \times 0.5}}$

${ = \tt{ - 1 +1.5}}$

${ = \tt{0.5}}$

${\star{\underline{\boxed{\tt{\red{0.5}}}}}}$

Hence, the answer is 0.5.

$\rule{300}{1.5}$