The solution examines the trajectory path for two stones that were thrown in the air. The option which adequately represents the solution is C. (Please see the attached image.)
Calculations for the first ball
Let's label the first stone S[tex]_{a}[/tex]:
The time calculated for Sa to hit the ground is given as follows:
- 240 = 10t - [tex]\frac{1}{2}[/tex]gt[tex]^{2}[/tex]
⇒ 5t - 10t -240
⇒ t² - 2t -48 = 0
⇒ t = 8, -6
The first stone therefore will hit the ground in 8 seconds.
With respect to the second stone,
- 240 = 40t - 5t²
⇒ t² - 8t - 48 = 0
t = 12 seconds.
The second stone, therefore, will hit the ground in 12 seconds.
To prove that the parabolic curve occurs, we can say:
Δy = y1 - y2 - 40t - [tex]\frac{1}{2}[/tex]gt² - 10t + [tex]\frac{1}{2}[/tex]gt² = 30t
Δy = 30t
After 8 seconds the second stone touches the grounds. This is given as:
y1 = - 240m
Therefore Δy = y2 - y1
= 40t - [tex]\frac{1}{2}[/tex]gt² + 240
Therefore after 8 seconds, the second stone will exhibit a parabolic trajectory on its way down.
The correct graph, therefore, is C.
Please see the link below for more about Parabolic Path:
https://brainly.com/question/24782990
