Question

a constant force of 391 n acts on a spacecraft of mass 7870 kg that has an initial velocity of 38 m/s. how far has the spacecraft traveled when it reaches a velocity of 4820 m/s?

Answer 1

Answer:

The distance travelled is 2.34*10^8 m.

Explanation:

The acceleration of the spacecraft is,

a=F/m

=391/7870 = 0.04968 m/s^2

The distance travelled,

d=v^2-v0^2/2a

=(4820)^2-(38)^2 / 2(0.04968)

=2.34*10^8 m.