Answer:
Impossible to say without knowing some sort of relationship between R, S and T
IF: Τ is the vertex of an angle θ
ΤΗΕΝ: RS = [tex]\sqrt{15^2 + 40^2 - 2(15)(40)cos\theta }[/tex]
Some special cases of note do occur
IF: θ = 0° so that cosθ = 1
THEN: RS = [tex]\sqrt{15^2 + 40^2 - 2(15)(40)}[/tex] = 25 ft
IF: θ = 90° or 270° so that cosθ = 0
THEN RS = [tex]\sqrt{15^2 + 40^2}[/tex] = [tex]\sqrt{1825}[/tex] ft or about 42.72 ft.
IF: θ = 180° so that cosθ = -1
THEN: RS = [tex]\sqrt{15^2 + 40^2 + 2(15)(40)}[/tex] = 55 ft
