Question

at what angle θ do you want to pull down on the end of the handle to maximize the torque your force causes?

Answer 1

Hi there!

Recall the equation for torque:

$\large\boxed{\tau = r \text{ x } F \text{ = } rFsin\theta}}$

For the torque to be a maximum, sinθ = 1. Thus:

sinθ = 1

θ = π/2 = 90°