Please help me! I don't understand how to do this!

Part 1: A 6 kg shopping cart goes from a velocity of 0.9 m/s to a velocity of 6 m/s over the course of 2.0 seconds. What is the cart's acceleration?​

Part 2: What is the net force acting on the shopping cart during that time? You will need your answer from the previous part.​

Respuesta :

Answer:

2.55 m/sec^2

Explanation:

Part 1: A 6 kg shopping cart goes from a velocity of 0.9 m/s to a velocity of 6 m/s over the course of 2.0 seconds. What is the cart's acceleration?​

The cart increases it's velocity by 5.1 m/sec.  Divide by the 2 seconds it took to make that change:

    (5.1 m/sec)/(2 sec) = 2.55 m/sec^2

Part 2: What is the net force acting on the shopping cart during that time? You will need your answer from the previous part.​

F = m*a

F = (6kg)*(2.55 m/sec^2)

F = 15.3 kg*m/sec^2

F = 15.3 Newtons

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