Question

Hey Guys !!!!

pls Help me out.....


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Answer 1

Answer:

D)  $3m + 21$

Step-by-step explanation:

We know that the average is a value divided by 2: So we can calculate the average in terms of x:

We know that:

$x = m + 9$

$y = 2m + 15$

$z = 3m + 18$

To find the average of x, y, z we can add them then we can divide by 2 to find the average in terms of m:

$m + 9 + 2m + 15 + 3m + 18 = 6m + 42$

I have combined like terms and then using that I can divide this by 2:

$6m + 42 / 2 = 3m + 21$

Answer 2

Answer:

Hey There!

Let's solve...

First we need to find out the equation of x which is

$x = \frac{m + 9}{2}$

Now let's find out the equation of y which is

$y = \frac{2m + 15}{2}$

Now let's find out equation of z which is

$z = \frac{3m + 18}{2}$

On adding the three equations, we get

$2x + 2y + 2z = m + 2m + 3m + 9 + 15 + 18$

Now we get..

$2(x + y + z) = 6m + 42 \\ \\ x + y + z = 3m + 21$

Now let's find our the average of x,y snd z which is

$\frac{x + y + z}{3} \\ which \: is \: \\ \\ \frac{3m + 21}{3}$

$now \: factor \: 3m + 21 \: which \\ is \: 3(m + 7)$

Now simplify..

$\frac{ \cancel{3}(m + 7)}{ \cancel{3}}$

So answer is m+7

I hope it is helpful to you..

Cheers!____________