Which of the following is an oxidation-reduction reaction? ZnS(s) 2O2(g) mc011-1. Jpg ZnSO4(s) CaO(s) H2O(l) mc011-2. Jpg Ca(OH)2(s) 6Li2O(s) P4O10(g) mc011-3. Jpg 4Li3PO4(s) SO2(g) H2O(l) mc011-4. Jpg H2SO3(aq).

Respuesta :

6Li2O(s) P4O10(g) mc011-3. Jpg 4Li3PO4(s) SO2(g)

The reaction in which there is a transfer of electrons between the two species occurs is called a redox reaction. The atoms undergo a change in oxidation states.

The following is the redox reaction:

Option A. [tex]\rm ZnS(s) + 2O_{2}(g) \rightarrow ZnSO_{4}(s)[/tex]

The redox reaction can be explained as:

  • The loss of an electron by element is called oxidation while its gain is called reduction. Oxidation-reduction is a reaction in which both the loss and gain of an electron occurs.

  • The increase in the oxidation number is said to be oxidation while when the oxidation state decreases it is called reduction.

  • In the reaction of zinc sulphide with oxygen, the oxidation number of [tex]\rm ZnS[/tex] is -2 while in the product formed zinc sulfate it is 4. It depicts that the [tex]\rm S[/tex] underwent oxidation.

  • The oxygen has 0 oxidation number but in [tex]\rm ZnSO_{4}[/tex], it is -2 that is oxygen underwent reduction.

Therefore, reaction A is correct.

To learn more about oxidation-reduction reactions follow the link:

https://brainly.com/question/7484802

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