Question

1) If the 10 kg sugar is Rs. 880 . Find the cost of 15 sugar

2) 50 students in a hostel have provisions for 21 days . How long would it last for 75 students?
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Answer 1

1) If the 10 kg sugar is Rs. 880 . Find the cost of 15 kg sugar.....

Solution,

let the required cost be Rs x

Here , the quantities of sugar and their cost are direct proportion

So, 10 : 15 = 8: x

$\: \frac{10}{15} = \frac{880}{x} \\ x = \frac{880 \times 15}{10} \\ x = Rs1320$

Hence , the cost of sugar is Rs.1320

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2) 50 students in a hostel have provisions for 21 days . How long would it last for 75 students?

Solution,

Let the required number of a day = x

Here , the number of student and the number of days are in inverse proportion.

•°• 50 : 75. = x : 21

$\frac{50}{75} = \frac{x}{21} \\ x = \frac{50 \times 21}{75} \\ x = 14 \: days$

Hence, the provisions last for 14 days for75 students

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Answer 2

1) The cost of 15 kg sugar is; Rs. 1320

2) The number of days that it would take the provisions to last for 75 students is; 14 days

Proportion

1) Cost of 10 kg = Rs. 880

Thus, by proportion the cost of 15 kg sugar will be;

(15 × 880)/10

>> 13200/10

>> Rs. 1320

2) We are told that;

50 students = provisions for 21 days

Thus for 75 students the number of days the provisions would last them is gotten by proportion;

(50 × 21)/75

>> 1050/75

>> 14 days

Read more about proportions at; https://brainly.com/question/1781657