The resulting equation will be [tex]-x+6=1[/tex], when the expression for y in the second equation is substituted into the first equation.
[tex]3x+y=1.....(1)\\[/tex]
[tex]y=6-4x........(2)[/tex]
According to the question, When the expression for y in the second equation is substituted into the first equation it means we have to put the value of [tex]y=6-4x[/tex] from equation (2) in equation (1).
[tex]3x+6-4x=1[/tex]
[tex]-x+6=1[/tex]
Hence the required equation is [tex]-x+6=1[/tex]. So the correct option is (A) [tex]-x+6=1[/tex].
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