The value of [tex]x[/tex] which satisfies the given quadratic equation is 4 and -6.
Given-
The given quadratic equation is.
[tex]x^2+2x=24[/tex]
Rewrite the given quadratic equation in the standard form,
[tex]x^2+2x-24=0[/tex]
Factorize the equation to find the value of [tex]x[/tex]. Apply the middle term splitting method. The above equation can be rewritten as,
[tex]x^2+6x-4x-24=0[/tex]
[tex]x(x+6)-4(x+6)=0[/tex]
[tex](x-4)(x+6)=0[/tex]
[tex]x=4,-6[/tex]
Hence, the value of [tex]x[/tex] which satisfies the given quadratic equation is 4 and -6.
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