Question

Solve the question ~







$\boxed{1 + 1 \div 2 \times 2 {}^{ - 1}}$
​

Answer 1

Answer:

The answer is 1.25.

Step-by-step explanation:

Solution :

$\dashrightarrow{\tt{1 + 1 \div 2\times {2}^{ - 1}}}$

According to the bodmas rule. Firstly, solving division

$\dashrightarrow{\tt{1 + \dfrac{1}{2} \times {2}^{ - 1}}}$

$\dashrightarrow{\tt{1 + \cancel{\dfrac{1}{2}} \times {2}^{ - 1}}}$

$\dashrightarrow{\tt{1 + 0.5 \times {2}^{ - 1}}}$

Now, using law of exponent rule to evaluate 2‐¹

$\dashrightarrow{\tt{1 + 0.5 \times \dfrac{1}{{2}^{1}}}}$

$\dashrightarrow{\tt{1 + 0.5 \times \dfrac{1}{2}}}$

$\dashrightarrow{\tt{1 + 0.5 \times \cancel{\dfrac{1}{2}}}}$

$\dashrightarrow{\tt{1 + 0.5 \times 0.5}}$

According to bodmas rule. Solving multiplication.

$\dashrightarrow{\tt{1 + \dfrac{5}{10} \times \dfrac{5}{10}}}$

$\dashrightarrow{\tt{1 + \dfrac{5 \times 5}{10 \times 10}}}$

$\dashrightarrow{\tt{1 + \dfrac{25}{100}}}$

$\dashrightarrow{\tt{1 + \cancel{\dfrac{25}{100}}}}$

$\dashrightarrow{\tt{1 + 0.25}}$

Now, according to bodmas rule. Solving addition.

$\dashrightarrow{\tt{1.25}}$

$\dag \: {\underline{\boxed{\frak{\red{1.25}}}}}$

Hence, the answer is 1.25.

$\begin{gathered}\end{gathered}$

Learn More :

✧ Algebraic identities :

⠀⇢ (a+b)²+(a-b)² = 2a²+2b²

⠀⇢ (a+b)²-(a-b)² = 4ab

⠀⇢ (a+b)(a -b) = a²-b²

⠀⇢ (a+b+c)² = a²+b²+c²+2ab+2bc+2ca

⠀⇢ (a-b)³ = a³-b³-3ab(a-b)

⠀⇢ (a³+b³) = (a+b)(a²-ab+b²)

⠀⇢ a²+b² = (a+b)²-2ab

⠀⇢ a³-b³ = (a-b)(a²+ab +b²)

⠀⇢ If a + b + c = 0 then a³ + b³ + c³ = 3abc

✧ BODMAS :

↝ BODMAS rule is an acronym used to remember the order of operations to be followed while solving expressions in mathematics.

It stands for :-

⠀ »» B - Brackets,

⠀ »» O - Order of powers or roots,

⠀ »» D - Division,

⠀ »» M - Multiplication 

⠀ »» A - Addition

⠀ »» S - Subtraction.

↝ It means that expressions having multiple operators need to be simplified from left to right in this order only.

✧ BODMAS RULE :

↝ First, we solve brackets, then powers or roots,then division or multiplication (whatever comes first from the left side of the expression), and then at last subtraction or addition.

⠀ ↠ Addition (+)

⠀ ↠ Subtraction (-)

⠀ ↠ Multiplication (×)

⠀ ↠ Division (÷)

⠀ ↠ Brackets ( )

✧ EXPONENT :

↝ The exponent of a number says how many times to use the number in a multiplication.

✧ LAW OF EXPONENT :

The important laws of exponents are given below:

⠀ ➠ ${\rm{{a}^{m} \times {a}^{n} = {a}^{m + n}}}$

⠀ ➠ ${\rm{{a}^{m}/{a}^{n} = {a}^{m - n}}}$

⠀ ➠ ${\rm{({a}^{m})^{n} = {a}^{mn}}}$

⠀ ➠ ${\rm{{a}^{n}/{b}^{n} = ({a/b})^{n} }}$

⠀ ➠ ${\rm{{a}^{0} = 1}}$

⠀ ➠ ${\rm{{a}^{ - m} = {1/a}^{m}}}$

⠀ ➠ ${\rm{{a}^{\frac{1}{n} } = \sqrt[n]{a}}}$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Answer 2

Applying the rule of PEDMAS, 1 + 1 ÷ 2 × 2^-1 = 1¼

What is the PEDMAS Rule?

Based on the PEDMAS rule, mathematical operations should be solved in the following order: parenthesis, exponents, division, multiplication, addition, and subtraction.

Given:

1 + 1 ÷ 2 × 2^-1

• Solve exponents

1 + 1 ÷ 2 × ½

• Divide

1 + ½ × ½

• Multiply

1 + ¼

• Add

1¼

Therefore, applying the rule of PEDMAS, 1 + 1 ÷ 2 × 2^-1 = 1¼

Learn more about PEDMAS on:

https://brainly.com/question/345677