Answer:
Sum of exterior angle is [tex]360^0[/tex]
Value of each exterior angle is [tex]120^0[/tex]
Step-by-step explanation:
Sum of interior angles of a polygon with n sides [tex]=(n-2)\times180[/tex]
Here
[tex](n-2)180=180\\\\n=3[/tex]
Hence the polygon is triangle
Sum of exterior angle is [tex]360^0[/tex]
Sum of one exterior angle
[tex]=\frac{360}{3} \\\\=120^0[/tex]