Question

Please help- not a test. 15pts.
The orthocenter of ΔABC lies at vertex A. What can you conclude about the line segments BA and AC? Explain.

Answer 1

Answer:

You can conclude that the line segments BA and AC are perpendicular to each other.

Step-by-step explanation:

That is because in this case, the triangle presented would be a right triangle. In right triangles, the orthocenter is the vertex of the triangle where two of the segments intersect perpendicularly, forming a 90 degree angle. As the orthocenter is where the altitudes intersect (altitudes are 90 degrees), we are able to conclude that BA and AC are perpendicular to each other.

Answer 2

Answer:

CE

AE

segment addition postulate

Given: ABC is a triangle.

To prove: BC + AC > BA

Proof: In triangle ABC, we can draw a perpendicular line segment from vertex C to segment AB. The intersection of AB and the perpendicular is called E. We know that BE is the shortest distance from B to CE and AE is the shortest distance from A to CE because of the shortest distance theorem.

Therefore,  and .

Now, add the inequalities, we get

.

Then,  because Segment addition postulate (states that given 2 points E and F, a third point D lies on the line segment EF if and only if the distances between the points satisfy the equation ED + DF = EF)

Therefore,  by substitution.

Step-by-step explanation: