The slope of B'C' is 1 and it can be determined by using formula of scale factor.
Given that,
ABC is an isosceles right triangle in which has a slope of -1 and m ∠ABC = 90°.
ABC is dilated by a scale factor of 1. 8 with the origin as the center of dilation, resulting in the image A'B'C'.
We have to determine,
What is the slope of B'C'?
According to the question,
ABC is an isosceles right triangle in which,
Slope of AB = -1
And AB is perpendicular to BC.
When the two lines are perpendicular to each other then,
[tex]\rm The \ slope\ of\ AB \times Slope\ of \ BC = -1\\\\-1 \times Slope\ of \ BC = -1\\\\ Slope\ of \ BC = 1\\[/tex]
ABC is dilated by a scale factor of 1. 8 with the origin as the center of dilation, resulting in the image A'B'C'.
Length of Line segment A'B'= 1.8 × AB
So, the slope of the two-line Segment that is AB and A'B' are the same.
Slope of A'B'= -1
Length of Line segment C'B'= 1.8 × CB
So, the slope of the two lines that is CB and C'B' are the same.
The slope of B'C' is 1.
Hence, The required slope of B'C' is 1.
For more details Slope refer to the link given below.
https://brainly.com/question/8102490
