Question One:
An Internet-based company that sells discount accessories for cell
phones often ships an excessive number of defective products. The
company needs better control of quality. Suppose it has 20 identical
car chargers on hand but that 5 are defective. If the company decides
to randomly select 10 of these items, what is the probability that 2 of
the 10 will be defective?

Respuesta :

Probability that 2 of the 10 chargers will be defective =0.35

Number of ways of selecting 10 chargers from 20 chargers is 20C10

20C10 = 184756

Number of ways of selecting 10 chargers from 20 = 184756

Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2

5C2 = 10

Since 2 defective chargers have been chosen, there remains 8 to choose

Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8

Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435

Probability that 2 of the 10 will be defective =

(10x6435)/184756

Probability that 2 of the 10 will be defective = 64350/184756

Probability that 2 of the 10 chargers will be defective =0.35

Learn more on probability here: https://brainly.com/question/24756209

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